MCu2GeS3 = 2 ∙ MCu + MGe + 3 ∙ MS = 2 ∙ 64 + 73 + 3 ∙ 32 = 128 + 73 + 96 = 297 [u]
%Ge =
∙ 100% = 24,57% = 24,6%
MAg8GeS6 = 8 ∙ MAg + MGe + 6 ∙ MS = 8 ∙ 108 + 73 + 6 ∙ 32 = 864 + 73 + 192 = 1129 [u]
%Ge =
∙ 100% = 6,46% = 6,5%
Odpowiedź: Zawartość germanu w germanicie Cu2GeS3 wynosi 24,6%, a w argyrodycie Ag8GeS6 wynosi 6,5%.
