Stechiometryczny stosunek: 1:1:1:1.
nC2H2OH = 5 – x
nCH3COOH = 4 – x
nCH3COOC2H5 = 3 + x
nH2O = x
Cm =
C2H5OH =
CH3COOH =
CH3COOC2H5 =
H2O =
K =
9 =
(3,64 – 0,91x) ∙ (4,55 – 0,91x) = 0,91x ∙ (2,73 + 0,91x)
16,562 – 3,3124x – 4,1405x + 0,8281x2 = 0,91x ∙ (2,73 + 0,91x)
16,562 – 7,4529x + 0,8281x2 = 2,4843x + 0,8281x2
– 7,4529x -2,4843x + 0,8281x2 - 0,8281x2 = -16,562
- 9,9372x = -16,562 /: (- 9,9372)
x = 1,67
C2H5OH =
CH3COOH =
CH3COOC2H5 =
H2O =