a) 12 mol/dm3 X i 0 mol/dm3 Y
b) 9 mol/dm3 X i 3 mol/dm3 Y
c) 3 mol/dm3 X i 9 mol/dm3 Y
d) 12 mol/dm3 X i 36 mol/dm3 Y
K = 
3 = 
3 ∙ (12 – a) = a
36 – 3a = a
- 3a – a = - 36
- 4a = -36 /: (-4)
a = 9
[X] = 9 mol/dm3
[Y] = 12 – 9 = 3 mol/dm3
Odpowiedź: C.
