Pc = Pp + Pb
|AE| = |ED| = 6 cm
|AS| = 10 cm
|AB| = 15 cm
Pp = |AB| · |AD|
|AD| = |AE| + |ED| = 6 cm + 6 cm = 12 cm
|SE|2 + |AE|2 = |AS|2
|SE|2 = 100 – 36 = 64 cm2
|SE| = 8 cm
|AB|2 + |AS|2 = |BS|2
152 + 102 = |BS|2
225 + 100 = |BS|2
|BS| = 5
|AE|2 + |XS|2 = |BS|2
62 + |XS|2 = 325
|XS|2 = 325 – 36
|XS| = 17
Pp = 15 cm · 12 cm = 180 cm2
Pc = Pp + Pb
Pc = 180 cm2 + 300 cm2 = 480 cm2
Pole powierzchni całkowitej ostrosłupa to suma pola powierzchni podstawy i pola powierzchni bocznej.